Questão 36 - 1ª Fase - ITA 2026

Dividindo 36 atm na proporção de 3 : 2 : 1, tem-se: 

18 atm de X : 12 atm de W : 6 atm de I

Assim: 

                                      $$\begin{gathered} 2\mathrm{X}\left(\mathrm{g}\right) + \mathrm{W}\left(\mathrm{g}\right) \stackrel{\mathrm{atm}}{\to } \mathrm{Y}\left(\mathrm{g}\right) + \mathrm{Z}\left(\mathrm{g}\right) \\ \mathrm{In}: 18 12 0 0 \\ \mathrm{R}: -18 -9 +9 +9 \\ \mathrm{F}: 0 3 9 9 \end{gathered}$$

 $$\begin{gathered} \mathrm{Dessa} \mathrm{forma}, {\mathrm{P}}_{\mathrm{total}} = {\mathrm{P}}_{\mathrm{W}} + {\mathrm{P}}_{\mathrm{Y}} + {\mathrm{P}}_{\mathrm{Z}} + {\mathrm{P}}_{\mathrm{I}} \\ {\mathrm{P}}_{\mathrm{total}} = 3 + 9 + 9 + 6 \Rightarrow {\mathrm{P}}_{\mathrm{total}} =\boxed{27 \mathrm{atm}} \end{gathered}$$